Ionisation Energy & Electronic Configuration (Cambridge International AS Chemistry)
Exam board Cambridge International · ASUpdated 2026-10-19
Ionisation Energies: Electronic Configuration
Using Successive Ionisation Energy Data
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Each ionisation energy refers to the energy required to remove one mole of electrons from one mole of a specific species in the gaseous state
- First ionisation energy is the energy required to remove one mole of electrons from one mole of gaseous atoms
- Successive ionisation energies are the energy required to remove one mole of electrons from one mole of gaseous positive ions
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As electrons are removed, the ion becomes more positively charged
- This increases the electrostatic attraction between the nucleus and remaining electrons
- Therefore, ionisation energies increase progressively
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A large jump in successive ionisation energies indicates that:
- An electron is being removed from a new, inner shell closer to the nucleus
- These electrons experience a stronger attraction to the nucleus and require more energy to remove
How to deduce electronic configuration
- Look for the largest increase between two successive ionisation energies
- The number of electrons removed before this jump = number of outer-shell (valence) electrons
- For Groups 1 and 2 this is the group number; for Groups 13 to 18 it is the group number minus 10 (for example, 7 outer-shell electrons means Group 17)
Worked Example Deduce the electronic configuration of element Z, a Period 3 element, using successive ionisation energy data.
IE 5th 6th 7th 8th IE (kJ mol-1) 6542 9362 11,018 33,606 Answer
You are told that the element is in Period 3
Period 3 elements have electrons up to the 3rd shell:
- 3s and 3p subshells are included
There is a large jump between the 7th and 8th IE, so element Z has 7 electrons in its outer shell and must be in Group 17
So element Z is in Period 3 and Group 17:
- This corresponds to chlorine, Cl
The electronic configuration of Cl is:
- 1s22s22p63s23p5
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