Which are correct for the reaction shown?
CH3COOH + KOH → CH3COO−K++ H2O ΔH = –55.8 kJ mol−1
| Type of reaction | Type of enthalpy change | ||
|---|---|---|---|
| ☐ | A | endothermic | formation |
| ☐ | B | endothermic | neutralisation |
| ☐ | C | exothermic | formation |
| ☐ | D | exothermic | neutralisation |
Choose your answer



