Operations with Numbers & Decimals (Cambridge International IGCSE Maths): Exam Questions

Edelgard tries to calculate $\frac{68+18}{9-5}$

She types into her calculator $68+18\div9-5.$

Explain why this does not give Edelgard the correct answer.

Work out the correct answer to $\frac{68+18}{9-5}.$

Work out $48\div3-5\times2$

Calculate $1.09+\frac{7.85}{6.21-4.37}$

Give your answer correct to 1 decimal place.

Calculate $3 + 2 \times ( 8 - 6 )$

Calculate $7 ( 2 \times 4 ) + 8 ( 2 + 6 )$

Insert one pair of brackets into this statement to make it correct.

7 × 5 – 2 + 3 = 42

Put one pair of brackets into the calculation to make it correct.

8 + 6 - 2 $\times$ 5 = 28

Put one pair of brackets into the calculation to make it correct.

8 + 6 - 2 $\times$ 5 = 60

Insert one pair of brackets to make this statement correct.

$4\times6-2+1=17$

Subtract 123 from 1 million.

Subtract 9 from 2.

i) Two numbers are added together to give the number in the box immediately above.

Complete the diagram.

ii) Two numbers are multiplied together to give the number in the box immediately above.

Complete the diagram.

Insert one pair of brackets to make this statement correct.

$3+2\times12-4=19$

Put one pair of brackets in each statement to make it correct.

$16\div8+4\times2=1$

$16\div8+4\times2=12$

Put one pair of brackets into each calculation to make it correct.

i) $24\div6+2\times3=9$

ii) $24\div6+2\times3=2$

Insert one pair of brackets in the following to make the statement correct.

$5+3\times10-1=32$

Insert one pair of brackets in the following to make the statement correct.

$3\times2-4-7=9$

Calculate $18 \div ( 10 - 4 ) - 11 \times 4 + 9 ( 6 + 1 )$

Jamie has incorrectly tried to calculate: $3 \times 2^{3} + \sqrt{25} ( 3^{2} \times 2 + 3 )$

His working is shown below.

$3 \times 2^{3} + \sqrt{25} ( 3^{2} \times 2 + 3 ) 3 \times 2^{3} + \sqrt{25} ( 40 ) 6^{3} + 5 ( 40 ) 216 + 200 416$

Identify the two mistakes that have been made, and find the correct final answer.